Integrand size = 25, antiderivative size = 226 \[ \int \frac {\csc ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^{5/2}} \, dx=-\frac {\left (5 a^2-10 a b+b^2\right ) \cot (e+f x)}{5 (a+b)^3 f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {2 (5 a+b) \cot ^3(e+f x)}{15 (a+b)^2 f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {\cot ^5(e+f x)}{5 (a+b) f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {4 b \left (5 a^2-10 a b+b^2\right ) \tan (e+f x)}{15 (a+b)^4 f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {8 b \left (5 a^2-10 a b+b^2\right ) \tan (e+f x)}{15 (a+b)^5 f \sqrt {a+b+b \tan ^2(e+f x)}} \]
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Time = 0.28 (sec) , antiderivative size = 226, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.240, Rules used = {4217, 473, 464, 277, 198, 197} \[ \int \frac {\csc ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^{5/2}} \, dx=-\frac {8 b \left (5 a^2-10 a b+b^2\right ) \tan (e+f x)}{15 f (a+b)^5 \sqrt {a+b \tan ^2(e+f x)+b}}-\frac {4 b \left (5 a^2-10 a b+b^2\right ) \tan (e+f x)}{15 f (a+b)^4 \left (a+b \tan ^2(e+f x)+b\right )^{3/2}}-\frac {\left (5 a^2-10 a b+b^2\right ) \cot (e+f x)}{5 f (a+b)^3 \left (a+b \tan ^2(e+f x)+b\right )^{3/2}}-\frac {\cot ^5(e+f x)}{5 f (a+b) \left (a+b \tan ^2(e+f x)+b\right )^{3/2}}-\frac {2 (5 a+b) \cot ^3(e+f x)}{15 f (a+b)^2 \left (a+b \tan ^2(e+f x)+b\right )^{3/2}} \]
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Rule 197
Rule 198
Rule 277
Rule 464
Rule 473
Rule 4217
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {\left (1+x^2\right )^2}{x^6 \left (a+b+b x^2\right )^{5/2}} \, dx,x,\tan (e+f x)\right )}{f} \\ & = -\frac {\cot ^5(e+f x)}{5 (a+b) f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}+\frac {\text {Subst}\left (\int \frac {2 (5 a+b)+5 (a+b) x^2}{x^4 \left (a+b+b x^2\right )^{5/2}} \, dx,x,\tan (e+f x)\right )}{5 (a+b) f} \\ & = -\frac {2 (5 a+b) \cot ^3(e+f x)}{15 (a+b)^2 f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {\cot ^5(e+f x)}{5 (a+b) f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}+\frac {\left (5 a^2-10 a b+b^2\right ) \text {Subst}\left (\int \frac {1}{x^2 \left (a+b+b x^2\right )^{5/2}} \, dx,x,\tan (e+f x)\right )}{5 (a+b)^2 f} \\ & = -\frac {\left (5 a^2-10 a b+b^2\right ) \cot (e+f x)}{5 (a+b)^3 f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {2 (5 a+b) \cot ^3(e+f x)}{15 (a+b)^2 f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {\cot ^5(e+f x)}{5 (a+b) f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {\left (4 b \left (5 a^2-10 a b+b^2\right )\right ) \text {Subst}\left (\int \frac {1}{\left (a+b+b x^2\right )^{5/2}} \, dx,x,\tan (e+f x)\right )}{5 (a+b)^3 f} \\ & = -\frac {\left (5 a^2-10 a b+b^2\right ) \cot (e+f x)}{5 (a+b)^3 f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {2 (5 a+b) \cot ^3(e+f x)}{15 (a+b)^2 f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {\cot ^5(e+f x)}{5 (a+b) f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {4 b \left (5 a^2-10 a b+b^2\right ) \tan (e+f x)}{15 (a+b)^4 f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {\left (8 b \left (5 a^2-10 a b+b^2\right )\right ) \text {Subst}\left (\int \frac {1}{\left (a+b+b x^2\right )^{3/2}} \, dx,x,\tan (e+f x)\right )}{15 (a+b)^4 f} \\ & = -\frac {\left (5 a^2-10 a b+b^2\right ) \cot (e+f x)}{5 (a+b)^3 f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {2 (5 a+b) \cot ^3(e+f x)}{15 (a+b)^2 f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {\cot ^5(e+f x)}{5 (a+b) f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {4 b \left (5 a^2-10 a b+b^2\right ) \tan (e+f x)}{15 (a+b)^4 f \left (a+b+b \tan ^2(e+f x)\right )^{3/2}}-\frac {8 b \left (5 a^2-10 a b+b^2\right ) \tan (e+f x)}{15 (a+b)^5 f \sqrt {a+b+b \tan ^2(e+f x)}} \\ \end{align*}
Time = 4.93 (sec) , antiderivative size = 173, normalized size of antiderivative = 0.77 \[ \int \frac {\csc ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^{5/2}} \, dx=\frac {(a+2 b+a \cos (2 (e+f x)))^3 \left (\frac {20 a b^2 (a+b)}{(a+2 b+a \cos (2 (e+f x)))^2}+\frac {10 a b (-6 a+5 b)}{a+2 b+a \cos (2 (e+f x))}+\left (-8 a^2+50 a b-15 b^2\right ) \csc ^2(e+f x)+2 (a+b) (-2 a+5 b) \csc ^4(e+f x)-3 (a+b)^2 \csc ^6(e+f x)\right ) \sec ^4(e+f x) \tan (e+f x)}{120 (a+b)^5 f \left (a+b \sec ^2(e+f x)\right )^{5/2}} \]
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Time = 6.23 (sec) , antiderivative size = 332, normalized size of antiderivative = 1.47
method | result | size |
default | \(-\frac {\left (b +a \cos \left (f x +e \right )^{2}\right ) \left (8 \cos \left (f x +e \right )^{8} a^{4}-80 \cos \left (f x +e \right )^{8} a^{3} b +40 \cos \left (f x +e \right )^{8} a^{2} b^{2}-20 a^{4} \cos \left (f x +e \right )^{6}+212 a^{3} b \cos \left (f x +e \right )^{6}-220 \cos \left (f x +e \right )^{6} a^{2} b^{2}+60 \cos \left (f x +e \right )^{6} a \,b^{3}+15 a^{4} \cos \left (f x +e \right )^{4}-180 \cos \left (f x +e \right )^{4} a^{3} b +378 a^{2} b^{2} \cos \left (f x +e \right )^{4}-180 \cos \left (f x +e \right )^{4} a \,b^{3}+15 \cos \left (f x +e \right )^{4} b^{4}+60 \cos \left (f x +e \right )^{2} a^{3} b -220 a^{2} b^{2} \cos \left (f x +e \right )^{2}+212 a \,b^{3} \cos \left (f x +e \right )^{2}-20 \cos \left (f x +e \right )^{2} b^{4}+40 a^{2} b^{2}-80 a \,b^{3}+8 b^{4}\right ) \sec \left (f x +e \right )^{5} \csc \left (f x +e \right )^{5}}{15 f \left (a^{5}+5 a^{4} b +10 a^{3} b^{2}+10 a^{2} b^{3}+5 a \,b^{4}+b^{5}\right ) \left (a +b \sec \left (f x +e \right )^{2}\right )^{\frac {5}{2}}}\) | \(332\) |
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Leaf count of result is larger than twice the leaf count of optimal. 460 vs. \(2 (206) = 412\).
Time = 9.34 (sec) , antiderivative size = 460, normalized size of antiderivative = 2.04 \[ \int \frac {\csc ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^{5/2}} \, dx=-\frac {{\left (8 \, {\left (a^{4} - 10 \, a^{3} b + 5 \, a^{2} b^{2}\right )} \cos \left (f x + e\right )^{9} - 4 \, {\left (5 \, a^{4} - 53 \, a^{3} b + 55 \, a^{2} b^{2} - 15 \, a b^{3}\right )} \cos \left (f x + e\right )^{7} + 3 \, {\left (5 \, a^{4} - 60 \, a^{3} b + 126 \, a^{2} b^{2} - 60 \, a b^{3} + 5 \, b^{4}\right )} \cos \left (f x + e\right )^{5} + 4 \, {\left (15 \, a^{3} b - 55 \, a^{2} b^{2} + 53 \, a b^{3} - 5 \, b^{4}\right )} \cos \left (f x + e\right )^{3} + 8 \, {\left (5 \, a^{2} b^{2} - 10 \, a b^{3} + b^{4}\right )} \cos \left (f x + e\right )\right )} \sqrt {\frac {a \cos \left (f x + e\right )^{2} + b}{\cos \left (f x + e\right )^{2}}}}{15 \, {\left ({\left (a^{7} + 5 \, a^{6} b + 10 \, a^{5} b^{2} + 10 \, a^{4} b^{3} + 5 \, a^{3} b^{4} + a^{2} b^{5}\right )} f \cos \left (f x + e\right )^{8} - 2 \, {\left (a^{7} + 4 \, a^{6} b + 5 \, a^{5} b^{2} - 5 \, a^{3} b^{4} - 4 \, a^{2} b^{5} - a b^{6}\right )} f \cos \left (f x + e\right )^{6} + {\left (a^{7} + a^{6} b - 9 \, a^{5} b^{2} - 25 \, a^{4} b^{3} - 25 \, a^{3} b^{4} - 9 \, a^{2} b^{5} + a b^{6} + b^{7}\right )} f \cos \left (f x + e\right )^{4} + 2 \, {\left (a^{6} b + 4 \, a^{5} b^{2} + 5 \, a^{4} b^{3} - 5 \, a^{2} b^{5} - 4 \, a b^{6} - b^{7}\right )} f \cos \left (f x + e\right )^{2} + {\left (a^{5} b^{2} + 5 \, a^{4} b^{3} + 10 \, a^{3} b^{4} + 10 \, a^{2} b^{5} + 5 \, a b^{6} + b^{7}\right )} f\right )} \sin \left (f x + e\right )} \]
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Timed out. \[ \int \frac {\csc ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^{5/2}} \, dx=\text {Timed out} \]
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Time = 0.20 (sec) , antiderivative size = 373, normalized size of antiderivative = 1.65 \[ \int \frac {\csc ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^{5/2}} \, dx=-\frac {\frac {40 \, b \tan \left (f x + e\right )}{\sqrt {b \tan \left (f x + e\right )^{2} + a + b} {\left (a + b\right )}^{3}} + \frac {20 \, b \tan \left (f x + e\right )}{{\left (b \tan \left (f x + e\right )^{2} + a + b\right )}^{\frac {3}{2}} {\left (a + b\right )}^{2}} - \frac {160 \, b^{2} \tan \left (f x + e\right )}{\sqrt {b \tan \left (f x + e\right )^{2} + a + b} {\left (a + b\right )}^{4}} - \frac {80 \, b^{2} \tan \left (f x + e\right )}{{\left (b \tan \left (f x + e\right )^{2} + a + b\right )}^{\frac {3}{2}} {\left (a + b\right )}^{3}} + \frac {128 \, b^{3} \tan \left (f x + e\right )}{\sqrt {b \tan \left (f x + e\right )^{2} + a + b} {\left (a + b\right )}^{5}} + \frac {64 \, b^{3} \tan \left (f x + e\right )}{{\left (b \tan \left (f x + e\right )^{2} + a + b\right )}^{\frac {3}{2}} {\left (a + b\right )}^{4}} + \frac {15}{{\left (b \tan \left (f x + e\right )^{2} + a + b\right )}^{\frac {3}{2}} {\left (a + b\right )} \tan \left (f x + e\right )} - \frac {60 \, b}{{\left (b \tan \left (f x + e\right )^{2} + a + b\right )}^{\frac {3}{2}} {\left (a + b\right )}^{2} \tan \left (f x + e\right )} + \frac {48 \, b^{2}}{{\left (b \tan \left (f x + e\right )^{2} + a + b\right )}^{\frac {3}{2}} {\left (a + b\right )}^{3} \tan \left (f x + e\right )} + \frac {10}{{\left (b \tan \left (f x + e\right )^{2} + a + b\right )}^{\frac {3}{2}} {\left (a + b\right )} \tan \left (f x + e\right )^{3}} - \frac {8 \, b}{{\left (b \tan \left (f x + e\right )^{2} + a + b\right )}^{\frac {3}{2}} {\left (a + b\right )}^{2} \tan \left (f x + e\right )^{3}} + \frac {3}{{\left (b \tan \left (f x + e\right )^{2} + a + b\right )}^{\frac {3}{2}} {\left (a + b\right )} \tan \left (f x + e\right )^{5}}}{15 \, f} \]
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\[ \int \frac {\csc ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^{5/2}} \, dx=\int { \frac {\csc \left (f x + e\right )^{6}}{{\left (b \sec \left (f x + e\right )^{2} + a\right )}^{\frac {5}{2}}} \,d x } \]
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Timed out. \[ \int \frac {\csc ^6(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^{5/2}} \, dx=\text {Hanged} \]
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